题解 | #蛇形矩阵#
蛇形矩阵
https://www.nowcoder.com/practice/649b210ef44446e3b1cd1be6fa4cab5e
n=int(input())
first_row=[(nn+1)*(nn+2)//2 for nn in range(n)]
for i in range(n):
for j in range(n-i):
print(first_row[i+j]-i,end=' ') # 使用i+j作为索引
print('')
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