题解 | #n的阶乘#
n的阶乘
https://www.nowcoder.com/practice/97be22ee50b14cccad2787998ca628c8
#include <iostream>
using namespace std;
long long Factorial(long long n){
if(n >= 1)
return n * Factorial(n - 1);
else
return 1;
}
int main() {
long long n;
cin >> n;
cout << Factorial(n);
return 0;
}
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