题解 | #判断链表中是否有环#
判断链表中是否有环
https://www.nowcoder.com/practice/650474f313294468a4ded3ce0f7898b9
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
#
# @param head ListNode类
# @return bool布尔型
#
class Solution:
def hasCycle(self , head: ListNode) -> bool:
st = set()
if head == None: #判断是不是空list,用head==None
return False
# if head.val == None:
# return False
while head: #list不为空的时候,一直遍历
l_set = len(st)
st.add(head)
if l_set == len(st):
return True
head = head.next
return False
为head地址建立一个set,每次往里加一个,看看长度变不变
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