题解 | #字符串加解密#
字符串加解密
https://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a
def jiami(string):
res = ""
for c in string:
if c == "z":
res += "A"
elif c == "Z":
res += "a"
elif "a" <= c <= "z":
res += chr(ord(c.upper()) + 1)
elif "A" <= c <= "Z":
res += chr(ord(c.lower()) + 1)
elif "0" <= c < "9":
res += chr(ord(c) + 1)
elif c == "9":
res += "0"
return res
def jiemi(string):
res = ""
for c in string:
if c == "a":
res += "Z"
elif c == "A":
res += "z"
elif "a" <= c <= "z":
res += chr(ord(c.upper()) - 1)
elif "A" <= c <= "Z":
res += chr(ord(c.lower()) - 1)
elif "0" < c <="9":
res += chr(ord(c) - 1)
elif c == "0":
res += "9"
return res
str1 = str(input())
str2 = str(input())
print(jiami(str1))
print(jiemi(str2))
投递科大讯飞等公司10个岗位 >
