题解 | #Coincidence#
Coincidence
https://www.nowcoder.com/practice/f38fc44b43cf44eaa1de407430b85e69
s0 = input()
s1 = input()
m, n = len(s0), len(s1)
dp = [[0 for i in range(n + 1)] for j in range(m + 1)]#dp是递推，大小需要多个1
for i in range(m):
for j in range(n):
if s0[i] == s1[j]:
dp[i + 1][j + 1] = dp[i][j] + 1
else:
dp[i + 1][j + 1] = max(dp[i][j + 1], dp[i + 1][j])
print(dp[m][n])
查看10道真题和解析
腾讯三面341人在聊