题解 | #整数与IP地址间的转换#
整数与IP地址间的转换
https://www.nowcoder.com/practice/66ca0e28f90c42a196afd78cc9c496ea
def reint(aa): a = aa.split(".") lenth = len(a) b = [] for i in range(lenth): b.append(bin(int(a[i]))) c = "".join(b) d = c.split("0b") e = [] for each in d: temp = "0" * (8 - len(each)) + each e.append(temp) f = e[1:] newd = "".join(f) print(int(newd, 2)) def reip(bb): s = bin(int(bb)) two = s[2:] lenth = len(two) ss = "0" * (32 - lenth) + str(two) if len(ss) <= 32: temp = (str(int(ss[0:8], 2))+ "."+ str(int(ss[8:16], 2))+ "."+ str(int(ss[16:24], 2))+ "."+str(int(ss[24:32], 2))) print(temp) #转换为2进制之后,最大32位 aa=input() bb=input() reint(aa) reip(bb)