题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param head ListNode类
# @param m int整型
# @param n int整型
# @return ListNode类
#
class Solution:
def reverseBetween(self , head: ListNode, m: int, n: int) -> ListNode:
# write code here
# total = 0
# tmp = head
# while tmp:
# total+=1
# tmp = tmp.next
cur = head
pre = None
idx = 0
while cur:
tmp = cur.next
if m==n:
return head
if (idx + 1 == m) and (m==1):
break0 = cur
if idx + 2 == m:
break1 = cur
break2 = cur.next
if idx < m:
pre = cur
else:
cur.next = pre
pre = cur
if idx + 1 == n:
if m==1:
break0.next = tmp
return pre
else:
break1.next = cur
break2.next = tmp
return head
cur = tmp
idx += 1
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