题解 | #质因数的个数#

def iss(x):#如果这两处不用根号降复杂度的话，会超时
    for i in range(2, int(x ** 0.5) + 1):
        if x % i == 0:
            return False
    if x == 1:
        return False
    return True


while True:
    try:
        n = int(input())
        ct = 1
        i = 1
        while i <= int(n ** 0.5):
            if n % i == 0 and iss(i):
                n = n // i
                ct = ct + 1
            else:
                i = i + 1
        print(ct)
    except:
        break