题解 | #螺旋矩阵#
螺旋矩阵
https://www.nowcoder.com/practice/7edf70f2d29c4b599693dc3aaeea1d31?tpId=295&tqId=693&ru=/exam/oj&qru=/ta/format-top101/question-ranking&sourceUrl=%2Fexam%2Foj%3Fpage%3D1%26tab%3D%25E7%25AE%2597%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D295
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param matrix int整型二维数组 # @return int整型一维数组 # class Solution: def spiralOrder(self , matrix: List[List[int]]) -> List[int]: # write code here L=[] while matrix: for i in range(len(matrix[0])): L.append(matrix[0][i]) matrix.remove(matrix[0]) #用python将矩阵逆时针翻转过来 matrix = list(map(list,zip(*matrix)))[::-1] return L