题解 | #最长公共前缀#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param strs string字符串一维数组 
# @return string字符串
#
class Solution:
    def longestCommonPrefix(self , strs: list[str]) -> str:
        # write code here
        if len(strs)==0:
            return ""
        L=[]
        for x in strs:
            length=len(x)
            L.append([x,length])
        
        L.sort(key=lambda x: x[1])
        minlenth=L[0][1]
        minlengthstring=L[0][0]
        while  minlengthstring in strs: 
            strs.remove(minlengthstring)
        for i in range(len(minlengthstring)):
            for j in strs:
                if minlengthstring[i]==j[i]:
                    pass
                else:
                    substring=minlengthstring[:i]
                    return substring
        return minlengthstring