题解 | #Redraiment的走法#
Redraiment的走法
https://www.nowcoder.com/practice/24e6243b9f0446b081b1d6d32f2aa3aa
import java.util.*;
// mark 一下
// 最长上升子序列问题
// each j < i && array[j] < array[i] -> dp[i] = Math.max(dp[i], dp[j] + 1);
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
while (in.hasNextInt()) {
int n = in.nextInt();
int[] array = new int[n + 1];
int[] dp = new int[n + 1];
for (int i = 1; i < n + 1; i++) {
array[i] = in.nextInt();
dp[i] = 1;
}
int ans = 0;
for (int i = 1; i < n + 1; i++) {
for (int j = 1; j < i; j++) {
if (array[i] > array[j]) {
dp[i] = Math.max(dp[j] + 1, dp[i]);
}
}
ans = Math.max(ans, dp[i]);
}
System.out.println(ans);
}
}
}

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