牛客网140道编程题源代码(51—100)

题解51| # 三角形判断 #

https://www.nowcoder.com/practice/689ec1e742394e09b1059556fc167b65

#include <stdio.h>

int main() 
{
    int a = 0;
    int b = 0;
    int c = 0;
    while(~scanf("%d %d %d",&a,&b,&c))
    {
        if((a+b>c)&&(a+c>b)&&(b+c>a))
        {
            if((a==b&&a!=c)||(a==c&&a!=b)||(b==c&&b!=a))
            {
                printf("Isosceles triangle!\n");
            }
            else if (a==b&&b==c)
            {
                printf("Equilateral triangle!\n");
            }
            else 
            {
                printf("Ordinary triangle!\n");
            }
        }
        else 
        {
            printf("Not a triangle!\n");
        }
    }
    return 0;
}

题解52| # 衡量人体胖瘦程度 #

https://www.nowcoder.com/practice/4d604603fae94a26b59b7bc18f363bc0

#include <stdio.h>

int main()
{
    int weight = 0;
    int hight = 0;
    while (scanf("%d %d", &weight, &hight) != EOF)
    {
        double BMI = weight / ((hight / 100.0) * (hight / 100.0));
        if (BMI < 18.5)
        {
            printf("Underweight\n");
        }
        else if (BMI >= 18.5 && BMI <= 23.8)
        {
            printf("Normal\n");
        }
        else if (BMI > 23.9 && BMI <= 27.9)
        {
            printf("Overweight\n");
        }
        else
        {
            printf("Obese\n");
        }
    }
    return 0;
}

题解53| # 计算一元二次方程 #

https://www.nowcoder.com/practice/7da524bb452441b2af7e64545c38dc26

#include <stdio.h>
#include <math.h>

int main()
{
    double a = 0.0;
    double b = 0.0;
    double c = 0.0;
    while (scanf("%lf %lf %lf", &a, &b, &c) != EOF)
    {
        if (a == 0)
        {
            printf("Not quadratic equation\n");
        }
        else
        {
            double disc = b * b - 4 * a * c;
            if (disc == 0)
            {
                if (b == 0 && c == 0)
                {
                    printf("x1=x2=0.00\n");
                }
                else
                    printf("x1=x2=%.2f\n", (-b) / (2 * a));
            }
            else if (disc > 0)
            {
                printf("x1=%.2lf;x2=%.2lf\n", (-b - sqrt(disc)) / (2 * a), (-b + sqrt(disc)) / (2 * a));
            }
            else
            {
                double real = (-b) / (2 * a);
                double image = sqrt(-disc) / (2 * a);
                printf("x1=%.2lf-%.2lfi;x2=%.2lf+%.2lfi\n", real, image, real, image);
            }
        }
    }
    return 0;
}

题解54| # 获得月份天数 #

https://www.nowcoder.com/practice/13aeae34f8ed4697960f7cfc80f9f7f6

 #include <stdio.h>

 int main()
 {
    int year = 0;
    int month = 0;
    int days[12]={31,28,31,30,31,30,31,31,30,31,30,31};
    while(~scanf("%d %d",&year,&month))
    {
        int day = days[month-1];
        if((year%4==0&&year%100!=0)||(year%400==0))
        {
           if(month==2)
           {
            day+=1;
           }  
        }
        printf("%d\n",day);
    }
    return 0;
 }

题解55| # 简单计算器 #

https://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239

#include <stdio.h>

int main() 
{
    double n1 = 0;
    double n2 = 0;
    char op = 0;
    scanf("%lf %c %lf",&n1,&op,&n2);
    switch(op)
    {
        case '+':
        printf("%.4lf+%.4lf=%.4lf\n",n1,n2,n1+n2);
        break;
        case '-':
        printf("%.4lf-%.4lf=%.4lf\n",n1,n2,n1-n2);
        break;
        case '*':
        printf("%.4lf*%.4lf=%.4lf\n",n1,n2,n1*n2);
        break;
        case '/':
        if(n2==0.0)
        {
            printf("Wrong!Division by zero!\n");
        }
        else 
        {
            printf("%.4lf/%.4lf=%.4lf\n",n1,n2,n1/n2);
        } 
        break;
        default:
        printf("Invalid operation!\n");
        break;
    }
    return 0;
}

题解56| # 线段图案 #

#include <stdio.h>

int main() 
{
    int n = 0;
    while(scanf("%d",&n)!=EOF)
    {
        int i = 0;
        for(i=0;i<n;i++)
        {
            printf("*");
        }
        printf("\n");
    }
    return 0;
}

题解57| # 正方形图案 #

#include <stdio.h>

int main() 
{
    int n = 0;
    while(scanf("%d",&n)!=EOF)
    {
        int i = 0;
        for(i=0;i<n;i++)
        {
            int j = 0;
            for(j = 0;j<n;j++)
            {
                printf("* ");
            }
            printf("\n");
        }
    }
    return 0;
}

题解58| # 直角三角形图案 #

#include <stdio.h>

int main()
{
    int n = 0;
    while (scanf("%d", &n)!=EOF)
    {
        int i = 0;
        for (i = 1; i <= n; i++)
        {
            int j = 0;
            for (j = 1; j <= i; j++)
            {
                printf("* ");
            }
            printf("\n");
        }
    }
    return 0;
}

题解59| # 翻转直角三角形图案 #

#include <stdio.h>

int main()
{
    int n = 0;
    while (scanf("%d", &n) != EOF)
    {
        int i = 0;
        for (i = 0; i < n; i++)
        {
            int j = 0;
            for (j = 0; j < n - i; j++)
            {
                printf("* ");
            }
            printf("\n");
        }
    }
    return 0;
}

题解60| # 带空格直角三角形图案 #

#include <stdio.h>

int main() 
{
    int n = 0;
    while(~scanf("%d",&n))
    {
        int i = 0;
        for(i = 1;i<=n;i++)
        {
            int j = 0;
            for(j = 1;j<=n-i;j++)
            {
                printf("  ");
            }
            for(j = 1;j<=i;j++)
            {
                printf("* ");
            }
            printf("\n");
        }
    }
    return 0;
}
#include <stdio.h>

int main()
{
    int n = 0;
    while (~scanf("%d", &n))
    {
        int i = 0;
        for (i = 0; i < n; i++)
        {
            int j = 0;
            for (j = 0; j < n - 1 - i; j++)
            {
                printf("  ");
            }
            for (j = 0; j <= i; j++)
            {
                printf("* ");
            }
            printf("\n");
        }
    }
    return 0;
}
#include <stdio.h>

int main() 
{
    int n = 0;
    while(~scanf("%d",&n))
    {
        int i = 0;
        for(i = 1;i<=n;i++)
        {
            int j = 0;
            for(j = 1;j<=n-i;j++)
            {
                printf("  ");
            }
            for(j = 1;j<=i;j++)
            {
                printf("* ");
            }
            printf("\n");
        }
    }
    return 0;
}

题解61| # 金字塔图案 #

#include <stdio.h>

int main() 
{
    int n = 0;
    while(scanf("%d",&n)!=EOF)
    {
        int i = 0;
        for(i = 1;i<=n;i++)
        {
            int j = 0;
            for(j=1;j<=n-i;j++)
            {
                printf(" ");
            }
            for(j=1;j<=i;j++)
            {
               printf("* ");
            }
            printf("\n");
        }
    }
    return 0;
}

题解62| # 翻转金字塔图案 #

#include <stdio.h>

int main()
{
	int n = 0;
	while (~scanf("%d", &n))
	{
		int i = 0;
		for (i = 0; i < n; i++)
		{
			int j = 0;
			for (j = 0; j < i; j++)
			{
				printf(" ");
			}
			for (j = 0; j < n - i; j++)
			{
				printf("* ");
			}
			printf("\n");
		}
	}
	return 0;
}

题解63| # 菱形图案 #

#include <stdio.h>

int main()
{
    int n = 0;
    while(scanf("%d",&n)!=EOF)
    {
        int i = 0;
        for(i=0;i<n;i++)
        {
           int j = 0;
           for(j = 0;j<n-i;j++)
           {
            printf(" ");
           }  
           for(j=0;j<=i;j++)
           {
            printf("* ");
           }
           printf("\n");
        }
        for(i = 0;i<n+1;i++)
        {
            int j = 0;
            for(j = 0;j<i;j++)
            {
                printf(" ");
            }
            for(j = 0;j<n+1-i;j++)
            {
                printf("* ");
            }
            printf("\n");
        }
    }
    return 0;
}

题解64| # K形图案 #

#include <stdio.h>

int main() 
{
    int n = 0;
    while(scanf("%d",&n)!=EOF)
    {
        int i = 0;
        for(i = 0;i<n;i++)
        {
            int j = 0;
            for(j = 0;j<n+1-i;j++)
            {
                printf("* ");
            }
            printf("\n");
        }
        for(i = 0;i<n+1;i++)
        {
            int j = 0;
            for(j = 0;j<=i;j++)
            {
                printf("* ");
            }
            printf("\n");
        }
    }
    return 0;
}

题解65| # 箭形图案 #

#include <stdio.h>

int main() 
{
    int n = 0;
    while(~scanf("%d",&n))
    {
        int i= 0;
        for(i = 0 ;i < n ;i++)
        {
            int j = 0;
            for(j = 0;j<n-i;j++)
            {
                printf("  "); 
            }
            for(j = 0;j<=i;j++)
            {
                printf("*");
            }
            printf("\n");
        }
        for(i = 0;i<n+1;i++)
        {
            int j = 0;
            for(j=0;j<i;j++)
            {
                printf("  ");
            }
            for(j=0;j<n+1-i;j++)
            {
                printf("*");
            }
            printf("\n");
        }
    }
    return 0;
}

题解66| # 反斜线形图案 #

#include <stdio.h>

int main() 
{
    int n = 0 ;
    while(scanf("%d",&n)!=EOF)
    {
        int i = 0;
        for(i = 0;i<n;i++)
        {
            int j = 0;
            for(j = 0;j<i;j++)
            {
                printf(" ");
            }
            printf("*\n");
        }
    }
    return 0;
}
#include <stdio.h>

int main() 
{
    int n = 0 ;
    while(scanf("%d",&n)!=EOF)
    {
        int i = 0;
        for(i = 0;i<n;i++)
        {
            int j = 0;
            for(j = 0;j<n;j++)
            {
                if(i == j)
                {
                    printf("*");
                }
                else 
                {
                    printf(" ");
                }
            }
            printf("\n");
        }
    }
    return 0;
}

题解67| # 正斜线形图案 #

#include <stdio.h>

int main() 
{
    int n = 0;
    while(scanf("%d",&n)!=EOF)
    {
        int i = 0;
        for(i = 0;i<n;i++)
        {
            int j = 0;
            for(j = 0;j<n-1-i;j++)
            {
                printf(" ");
            }
            printf("*\n");
        }
    }
    return 0;
}
#include <stdio.h>
int main()
{
    int n = 0;
    while (scanf("%d", &n) != EOF)
    {
        int i = 0;
        for (i = 0; i < n; i++)
        {
            int j = 0;
            for (j = 0; j < n; j++)
            {
                if (i + j == n - 1)
                    printf("*");
                else
                    printf(" ");
            }
            printf("\n");
        }
    }
    return 0;
}

题解68| # X形图案 #

#include <stdio.h>

int main() 
{
    int n = 0;
    while(scanf("%d",&n)!=EOF)
    {
        int i = 0;
        for(i = 0;i<n;i++)
        {
            int j = 0;
            for(j = 0;j<n;j++)
            {
                if(i==j||i+j==n-1)
                {
                printf("*");
                }
                else
                {
                printf(" ");
                }
            }
            printf("\n");
         }   
    }
    return 0;
}
#include <stdio.h>

int main() 
{
    int n = 0;
    while(scanf("%d",&n)!=EOF)
    {
        int i = 0;
        for(i = 0;i<n;i++)
        {
            int j = 0;
            for(j = 0;j<n;j++)
            {
                if(i==j)
                {
                printf("*");
                }
                else if(i+j==n-1)
                {
                   printf("*"); 
                }
                else
                {
                printf(" ");
                }
            }
            printf("\n");
         }   
    }
    return 0;
}

题解69| # 空心正方形图案 #

#include <stdio.h>

int main()
{
    int n = 0;
    while (scanf("%d", &n) != EOF)
    {
        int i = 0;
        for (i = 0; i < n; i++)
        {
            int j = 0;
            for (j = 0; j < n; j++)
            {
                if (i == 0 || i == n - 1)
                {
                    printf("* ");
                }
                else if (j == 0 || j == n - 1)
                {
                    printf("* ");
                }
                else 
                {
                    printf("  ");
                }
            }
            printf("\n");
        }
    }
    return 0;
}

题解70| # 空心三角形图案 #

#include <stdio.h>

int main()
{
    int n = 0;
    while (scanf("%d", &n) != EOF)
    {
        int i = 0;
        for (i = 0; i < n; i++)
        {
            int j = 0;
            for (j = 0; j < n; j++)
            {
                if (j == 0 || i == j || i == n - 1)
                {
                    printf("* ");
                }
                else {
                    printf("  ");
                }
            }
            printf("\n");
        }
    }
    return 0;
}

题解71| # 新年快乐 #

#include <stdio.h>

int main()
{
    printf("Happy New Year*2019*\n");

    return 0;
}

题解72| # 平均身高 #

#include <stdio.h>

int main()
{
    double hight[5] = { 0 };
    int i = 0;
    double sum = 0;
    double div = 0;
    for (i = 0; i < 5; i++)
    {
        scanf("%lf", &hight[i]);
        sum = sum + hight[i];
    }
    div = sum / 5;
    printf("%.2lf\n", div);
    return 0;
}

题解73| # 挂科危险 #

#include <stdio.h>

int main()
{
    int credit = 0;
    scanf("%d", &credit);
    if (credit >= 0 && credit <= 3)
    {
        printf("Good\n");
    }
    else if (credit >= 4 && credit <= 9)
    {
        printf("Danger\n");
    }
    else
    {
        printf("Danger++\n");
    }

    return 0;
}

题解74| # HTTP状态码 #

#include <stdio.h>

int main()
{
    int n = 0;
    while (scanf("%d", &n) != EOF)
    {
        if (n == 200)
        {
            printf("OK\n");
        }
        else if (n == 202)
        {
            printf("Accepted\n");
        }
        else if (n == 400)
        {
            printf("Bad Request\n");
        }
        else if (n == 403)
        {
            printf("Forbidden\n");
        }
        else if (n == 404)
        {
            printf("Not Found\n");
        }
        else if (n == 500)
        {
            printf("Internal Server Error\n");
        }
        else if (n == 502)
        {
            printf("Bad Gateway\n");
        }
    }

    return 0;
}

题解75| # 数字三角形 #

#include <stdio.h>

int main()
{
    int n = 0;
    while (scanf("%d", &n) != EOF)
    {
        int i = 0;
        for (i = 1; i <= n; i++)
        {
            int j = 0;
            for (j = 1; j <= i; j++)
            {
                printf("%d ", j);
            }
            printf("\n");
        }
    }
    return 0;
}

题解76| # 公务员面试 #

#include <stdio.h>

int main()
{
	int score[7] = { 0 };
	while (~scanf("%d %d %d %d %d %d %d", &score[0], &score[1], &score[2], &score[3], &score[4], &score[5], &score[6]))
	{
		int i = 0;
		int max = 0;
		int sum = 0;
		int min = 100;
		for (i = 0; i < 7; i++)
		{
			sum += score[i];
			if (score[i] > max)
			{
				max = score[i];
			}
			if (score[i] < min)
			{
				min = score[i];
			}
		}
		printf("%.2lf\n", (sum - min - max) / 5.0);
	}
	return 0;
}

题解77| # 有序序列插入一个数 #


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题解101| # 班级成绩的输入输出 #

#include <stdio.h>

int main()
{
    double score[5] = { 0.0 };
    int i = 0;
    for (i = 0; i < 5; i++)
    {
        int j = 0;
        double sum = 0.0;
        for (j = 0; j < 5; j++)
        {
            scanf("%lf", &score[j]);
            printf("%.1lf ", score[j]);
            sum += score[j];
        }
        printf("%.1lf\n", sum);
    }
    return 0;
}
#include <stdio.h>

int main() 
{
    double score[5]={0.0};
    int i = 0;
    while(i<5)
    {
        int j = 0;
        double sum  = 0.0;
        while(j<5)
        {
            scanf("%lf",&score[j]);
            sum +=score[j];
            j++;
        }
        j = 0;
        while(j<5)
        {
            printf("%.1lf ",score[j]);
            j++;
        }
        printf("%.1lf\n",sum);
        i++;
    }
    return 0;
}

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