题解 | #字符串加密#
字符串加密
https://www.nowcoder.com/practice/e4af1fe682b54459b2a211df91a91cf3
key = input()
str1 = input()
key = [i for i in key] # 转为单个的字符列表
new_key = []
for i in key: # 去重,保留第一次出现的字符
if i not in new_key:
new_key.append(i)
new_key = "".join(new_key) # 去重后的key
zmb = "abcdefghijklmnopqrstuvwxyz" # 定义字母表
zmb_t = new_key + zmb # 组合newkey和字母表,再去重后即为新的字母表
new_zmb = []
for i in zmb_t:
if i not in new_zmb:
new_zmb.append(i)
d_zmb = "".join(new_zmb)
new_str1 = []
for i in str1: # 加密,取原来字母表的索引,用新字母表的值
for index, value in enumerate(zmb):
if i in value:
new_str1.append(new_zmb[index])
print("".join(new_str1))