力扣(leetcode) 2000. 反转单词前缀

class Solution(object):
    def reversePrefix(self, A, ch):
        """
        :type word: str
        :type ch: str
        :rtype: str
        """
        ind = -1
        for i, a in enumerate(A):
            if ch == a: 
                ind = i
                break
        return A[0:ind+1][::-1] + A[ind+1:]

作者：Jack

链接：https://leetcode.cn/problems/reverse-prefix-of-word/solutions/1966008/by-jack-oi-oj8p/

来源：力扣（LeetCode）

著作权归作者所有。商业转载请联系作者获得授权，非商业转载请注明出处。

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```

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```