华为机试二星题--解密犯罪时间
我的想法先从分钟起加时间，如果能凑成就输出
如果凑成的数字小于原始分钟，说明时针+1
如果除了原始分钟凑不出任何一对，就凑时针
算法不用 没用回溯 用了字典 python3实现
n, m = input().split(':')
s = n + m
d = set(s)
def search(l):
d1 = set(l)
if d1 <= d:
return True
else:
return False
mn = 0
nn=int(n)
shi = [i for i in range(1, 25)]
fen = [i for i in range(1, 61)]
fenn = fen[int(m):] + fen[:int(m)-1]
for each in fenn:
if search(str(each)):
mn = each
break
if mn<int(m):
nn=int(n)+1
shin = shi[int(nn):] + shi[:int(nn)]
if not mn:
for each in shin:
if search(str(each)):
nn = each
mn = m
break
if mn<10:
mn='0'+str(mn)
if nn<10:
nn='0'+str(nn)
print(':'.join([str(nn), str(mn)])) 
