题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
使用lambda表达式完成对列表元素的运算
list_n = [[1,2,3],[4,5,6],[7,8,9]] n = int(input()) list_m = [] for i in list_n: listi = list(map(lambda a:a*n,i)) list_m.append(listi) print(list_m)