题解 | #字符串加解密#
字符串加解密
https://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a
大小写字母相差32即0x20，按位异或即可转换
int main()
{
char str[1001];
scanf("%s", str);
for(int i=0; i<strlen(str); i++)
{
if(str[i]=='Z')
str[i] = 'a';
else if(str[i]=='z')
str[i] = 'A';
else if(str[i]=='9')
str[i] = '0';
else if(str[i]>='0' && str[i]<='8')
str[i] += 1;
else
str[i] = (str[i]^0x20) + 1;//大小写相差32即0x20，按位异或即可转换
}
printf("%s\n", str);
scanf("%s", str);
for(int i=0; i<strlen(str); i++)
{
if(str[i]=='a')
str[i] = 'Z';
else if(str[i]=='A')
str[i] = 'z';
else if(str[i]=='0')
str[i] = '9';
else if(str[i]>='1' && str[i]<='9')
str[i] -= 1;
else
str[i] = (str[i]^0x20) - 1;
}
printf("%s\n", str);
}
