题解 | #识别有效的IP地址和掩码并进行分类统计#
识别有效的IP地址和掩码并进行分类统计
https://www.nowcoder.com/practice/de538edd6f7e4bc3a5689723a7435682
利用正则表达式匹配有效地IP地址和子网掩码
import re
ip_pattern = re.compile(
r'(?=(\b))(((\d{1,2})|(1\d{1,2})|(2[0-4]\d)|(25[0-5]))\.){3}((\d{1,2})|(1\d{1,2})|(2[0-4]\d)|(25[0-5]))(?=(\b))')
mask_pattern = re.compile(r'^1+0+$')
# A、B、C、D、E、错误IP地址或错误掩码、私有IP的个数
cnt = [0, 0, 0, 0, 0, 0, 0]
# private = [10, 172, 192]
while 1:
try:
origList = input().split('~') # ['10.70.44.68'. '255.254.255.0']
ipstr, maskcode = origList[0], origList[1]
maskList = maskcode.split('.')
masks = [str(bin(int(m))) for m in maskList]
mask2 = [a[2:].zfill(8) for a in masks]
maskstr = ''.join(mask2)
if re.match(ip_pattern, ipstr):
ipNum = ipstr.split('.')
ipOne = int(ipNum[0])
ipTwo = int(ipNum[1])
# 忽略条件
if ipOne == 127 or ipOne == 0:
continue
# 私有IP
'''
私网IP范围是：
从10.0.0.0到10.255.255.255
从172.16.0.0到172.31.255.255
从192.168.0.0到192.168.255.255
'''
if re.match(mask_pattern, maskstr): # and re.match(bin_pattern, maskstr):
if (1 <= ipOne <= 126):
cnt[0] += 1
if ipOne == 10:
cnt[-1] += 1
elif (ipOne < 192):
cnt[1] += 1
if ipOne == 172 and 16 <= ipTwo <= 31:
cnt[-1] += 1
elif ipOne < 224:
cnt[2] += 1
if ipOne == 192 and ipTwo == 168:
cnt[-1] += 1
elif ipOne < 240:
cnt[3] += 1
else:
cnt[4] += 1
else:
cnt[5] += 1
# 错误的IP或子网掩码
else:
cnt[5] += 1
except:
break
print(' '.join([str(i) for i in cnt]))
