题解 | #识别有效的IP地址和掩码并进行分类统计#

import re

ip_pattern = re.compile(
    r'(?=(\b))(((\d{1,2})|(1\d{1,2})|(2[0-4]\d)|(25[0-5]))\.){3}((\d{1,2})|(1\d{1,2})|(2[0-4]\d)|(25[0-5]))(?=(\b))')
mask_pattern = re.compile(r'^1+0+$')

#    A、B、C、D、E、错误IP地址或错误掩码、私有IP的个数
cnt = [0, 0, 0, 0, 0, 0, 0]
# private = [10, 172, 192]
while 1:
    try:
        origList = input().split('~')  # ['10.70.44.68'. '255.254.255.0']
        ipstr, maskcode = origList[0], origList[1]
        maskList =  maskcode.split('.')
        
        masks = [str(bin(int(m))) for m in maskList]
        mask2 = [a[2:].zfill(8) for a in masks]
        maskstr = ''.join(mask2)
        if re.match(ip_pattern, ipstr):
            ipNum = ipstr.split('.')
            ipOne = int(ipNum[0])
            ipTwo = int(ipNum[1])
            # 忽略条件
            if ipOne == 127 or ipOne == 0:
                continue

            # 私有IP
            '''
            私网IP范围是：
            从10.0.0.0到10.255.255.255
            从172.16.0.0到172.31.255.255
            从192.168.0.0到192.168.255.255
            '''
            if re.match(mask_pattern, maskstr): # and re.match(bin_pattern, maskstr):
                if (1 <= ipOne <= 126):
                    cnt[0] += 1
                    if ipOne == 10:
                        cnt[-1] += 1
                elif (ipOne < 192):
                    cnt[1] += 1
                    if ipOne == 172 and  16 <= ipTwo <= 31:
                        cnt[-1] += 1
                elif ipOne < 224:
                    cnt[2] += 1
                    if ipOne == 192 and ipTwo == 168:
                        cnt[-1] += 1
                elif ipOne < 240:
                    cnt[3] += 1
                else:
                    cnt[4] += 1
            else:
                cnt[5] += 1
        # 错误的IP或子网掩码
        else:
            cnt[5] += 1

    except:
        break
print(' '.join([str(i) for i in cnt]))