题解 | #连续子数组的最大乘积#
一开始使用Integer类型保存会WA，使用nextLong进行变量保存之后就可以AC了
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
int n = reader.nextInt();
long[] nums = new long[n];
for (int i = 0; i < n; i++) {
nums[i] = reader.nextLong();
}
long imax = 1;
long imin = 1;
long res = Long.MIN_VALUE;
for (int i = 0; i < n; i++) {
if (nums[i] < 0) {
long t = imax;
imax = imin;
imin = t;
}
imax = Math.max(imax * nums[i], nums[i]);
imin = Math.min(imin * nums[i], nums[i]);
res = Math.max(res, imax);
}
System.out.println(res);
}
