题解 | #计算日期到天数转换#

#include<stdio.h>
int Day(int y, int m, int d)
{
    if ((y % 4 == 0) && (y % 100 != 0) || (y % 400 == 0))
    {
        int c = 0;
        int x[12] = { 31,29,31,30,31,30,31,31,30,31,30,31 };
        for (int i = 0; i < m - 1; i++)
        {
            c += x[i];
        }
        return c + d;
    }
    else
    {
        int c = 0;
        int x[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
        for (int i = 0; i < m - 1; i++)
        {
            c += x[i];
        }
        return c + d;
    }
}
int main()
{
    int year = 0;
    int month = 0;
    int day = 0;
    int x = 0;
    scanf("%d %d %d", &year, &month, &day);
    x = Day(year, month, day);
    printf("%d", x);
    return 0;
}