题解 | #上三角矩阵判定#
上三角矩阵判定
https://www.nowcoder.com/practice/f5a29bacfc514e5a935723857e1245e4
#include<stdio.h> int main() { int n = 0; scanf("%d", &n);//表示方阵的n行n列,1≤n≤10 int arr[10][10] = { 0 }; int i = 0; int j = 0; for (i = 0; i < n; i++) { for (j = 0; j < n; j++) { scanf("%d", &arr[i][j]); } } int count = 0; for (i = 1; i < n; i++) { for (j = 0; j < i; j++) { if (0 == arr[i][j]) count++; } } if (count == (n * n - n) / 2) printf("YES\n"); else printf("NO\n"); return 0; }