题解 | #配置文件恢复#

思路：

1. 需要按照是否有空格来把命令区分为两类。
2. 前一类仅有一个。
3. 后一类按照空格所在的位置进行比较，注意需要判断比较符合的条件是否仅有一个，多个也应该视为unknown command(不知道)

#include <stdio.h>

static char *cmd1[6] = {"reset", "reset", "board", "board", "reboot", "backplane"};
static char *cmd2[6]= {"no use", "board", "add", "delete", "backplane", "abort"};

static int output_cmd(int flag)
{
    switch(flag)
    {
        case 0:
            printf("reset what\n");
            break;
        case 1:
            printf("board fault\n");
            break;
        case 2:
            printf("where to add\n");
            break;
        case 3:
            printf("no board at all\n");
            break;
        case 4:
            printf("impossible\n");
            break;
        case 5:
            printf("install first\n");
            break;
        default:
            printf("unknown command\n");
            break;   
    }
    return 0;
}

/* 判断字符串是否有空格，如果有，通过index_space参数获取空格位置 */
static int isSpace(char *str, int *index_space)
{
    *index_space = 0;
    if(!str)
    {
        return -1;
    }
    int flag_space = 0;
    int len = strlen(str);
    for(int i = 0; i < len; i++)
    {
        if(str[i] == ' ')
        {
            flag_space = 1;
            *index_space = i;
            break;
        }
    }
    return flag_space;
}

int main()
{
    char order[800][20];
    memset(order , 0, 800*20*sizeof(char));
    int index = 0;
    while(gets(order[index]))
    {
        //printf("order[%d] = %s\n", index, order[index]);
        index++;
    }
    //printf("index = [%d]\n", index);
    int output[index][20];
    memset(output , 0, index*20*sizeof(char));
    for(int i = 0; i < index; i++)
    {
        int index_space = 0;
        if(isSpace(order[i], &index_space) == 1)
        {
            /* 说明有空格 */
            int flag = -1;
            int count = 0;
            for(int j = 1; j < 6; j++)
            {
                if(strncmp(order[i], cmd1[j], index_space) == 0
                  && strncmp(order[i]+index_space+1, cmd2[j], strlen(order[i])-index_space-1) == 0)
                {
                    count++;    //如果有两个符合条件的，也要输出unknown command
                    flag = j;
                }
            }
            if(count == 1 && flag >= 0)
            {
                output_cmd(flag);
            }
            else
            {
                output_cmd(6);
            }
        }
        else
        {
            if(strncmp(order[i], cmd1[0], strlen(order[i])) == 0)	//需要和输入的字符串长度比较
            {
                output_cmd(0);
            }
            else
            {
                output_cmd(6);
            }
        }
    }
    
    return 0;
}