题解 | #求int型正整数在内存中存储时1的个数#
求int型正整数在内存中存储时1的个数
http://www.nowcoder.com/practice/440f16e490a0404786865e99c6ad91c9
number = int(input()) dig = bin(number) list1 = list(dig) list1.reverse() str1 = ''.join(list1) count = 0 for i in str1: if i == '1' or i == '0': if i == '1': count = count + 1 else: break print(count)
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