题解 | #合并两个排序的链表#
合并两个排序的链表
http://www.nowcoder.com/practice/d8b6b4358f774294a89de2a6ac4d9337
/*
public class ListNode {
int val;
ListNode next = null;
ListNode(int val) {
this.val = val;
}
}*/
public class Solution {
public ListNode Merge(ListNode list1,ListNode list2) {
ListNode newHead=null;
ListNode cur=null;
if(list1==null){
return list2;
}
else if(list2==null){
return list1;
}
if(list1.val<=list2.val){
newHead=list1;
cur=newHead;
list1=list1.next;
}else{
newHead=list2;
cur=newHead;
list2=list2.next;
}
while(list1!=null&&list2!=null){
if(list1.val<=list2.val){
cur.next=list1;
list1=list1.next;
cur=cur.next;
}
else{
cur.next=list2;
list2=list2.next;
cur=cur.next;
}
}
if(list1!=null){
cur.next=list1;
}else{
cur.next=list2;
}
return newHead;
}
}
public class ListNode {
int val;
ListNode next = null;
ListNode(int val) {
this.val = val;
}
}*/
public class Solution {
public ListNode Merge(ListNode list1,ListNode list2) {
ListNode newHead=null;
ListNode cur=null;
if(list1==null){
return list2;
}
else if(list2==null){
return list1;
}
if(list1.val<=list2.val){
newHead=list1;
cur=newHead;
list1=list1.next;
}else{
newHead=list2;
cur=newHead;
list2=list2.next;
}
while(list1!=null&&list2!=null){
if(list1.val<=list2.val){
cur.next=list1;
list1=list1.next;
cur=cur.next;
}
else{
cur.next=list2;
list2=list2.next;
cur=cur.next;
}
}
if(list1!=null){
cur.next=list1;
}else{
cur.next=list2;
}
return newHead;
}
}