题解 | #最高分与最低分之差#

int main() {
    int n;
    scanf("%d", &n);
    int m[n];
    for (int i = 0; i < n; i++) {
        scanf("%d ", &m[i]);
    }
    int max = m[0], min = m[0];
    for (int j = 0; j < n; j++) {
        if (m[j] > max) max = m[j];
        if (m[j] < min) min = m[j];
    }
    printf("%d", max - min);
    return 0;
}