阿里笔试 9.3
第一题: 输入字符串A,B 只有0、1组成,在[i,j] 范围中1变成0,0变成1,求最少需要多少次使得A变成B
样例 :
3
100
011
输出:1
说明 在[1,3] 中A 变换1次: 100 -> 011
3
101
000
2
AC
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = Integer.parseInt(scanner.nextLine());
String A = scanner.nextLine();
String B = scanner.nextLine();
int j =0 ,count = 0;
int [] dp = new int[n];
for (int i = 0; i < n; i++) {
if (A.charAt(i)!=B.charAt(i)) dp[i] = 0;
else dp[i] = 1;
}
for (int i = 0; i < n; i++) {
if (dp[i] == 0) j++;
else {
if (j>0)count++;
j=0;
}
}
if (j>0)count++;
System.out.println(count);
}
} 第二题:A、B、C 三个数 ,求 x,y 的组合次数,使得满足下面条件:
A<= x*x<=B
A<= y*y*y<=B
|x*x - y*y*y| <=c
正确率: 21.67%
public class Main02 {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
double a = scanner.nextDouble();
double b = scanner.nextDouble();
double c = scanner.nextDouble();
double i = Math.sqrt(a);
double j = Math.sqrt(a);
long count = 0;
for (;i<Math.sqrt(b);i++){
for (;j*j*j<b;j++)
if (Math.abs(i*i-j*j*j)<=c) count++;
}
String res = String.valueOf(count);
System.out.println(res.substring(0,res.length()-2));
}
}

荣耀工作强度 439人发布