360笔试AC代码
题比较简单，直接贴代码
1. 格式化字符串(string遍历)
int main() {
string s;
cin >> s;
if (s.size() == 0) {
cout << s << endl;
return 0;
}
s += 'n';
int index = 1, last = 0;
vector<string> ans;
while (s.find('n', index) != s.npos) {
int cur = s.find('n', index);
string t = s.substr(last, cur-last);
t[0] -= 32;
ans.push_back(t);
if (cur == s.size()-1) break;
last = cur;
index = cur+1;
}
for (int i = 0; i < ans.size(); i++) cout << ans[i] << endl;
return 0;
} 2. 背包问题
实测：不进行状态空间压缩只能通过27%
int main() {
int m, n;
cin >> m >> n;
vector<vector<int>> nums(m, vector<int>(n, 0));
vector<int> f(n+1, 0);
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
int t;
cin >> t;
nums[i][j] = t;
}
}
for (int i = 1; i <= m; i++) {
for (int v = n; v >= 1; v--) {
for (int k = v; k >= 1; k--) {
f[v] = max(f[v], f[v-k]+nums[i-1][k-1]);
}
}
}
cout << f[n] << endl;
return 0;
} 
投递字节跳动等公司9个岗位