java多行输入判断是否完成

其中一种是这样，就是过不了，好气啊 import java.util.Scanner; public class Main {     public static void main(String[] args) {         Scanner sc=new Scanner(System.in);         int n;         while(sc.hasNext()){         n=sc.nextInt();             System.out.println(sum(n));         }         sc.close();     }     public static int sum(int i){         if(i<=4){             return i;         }else{             return sum(i-1)+sum(i-3);         }     } }

https://yinziang.github.io/yinziang/2018/03/05/Algo-OJ-Others-3/ 这边有总结输入的套路，公司真题和牛客OJ都阔以过的说

Scanner scanner = new Scanner(System.in); while (scanner.hasNext()) { int param1 = scanner.nextInt(); int param2 = scanner.nextInt(); int param3 = scanner.nextInt(); System.out.println(result1); System.out.println(result2); System.out.println(result3); }

可以设置退出的字符串，当输入该字符串时退出