题解 | #排序奇升偶降链表#
排序奇升偶降链表
http://www.nowcoder.com/practice/3a188e9c06ce4844b031713b82784a2a
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* ListNode(int x) : val(x), next(nullptr) {}
* };
*/
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @return ListNode类
*/
//类似leetcode328奇偶链表,去掉链表合并步骤
ListNode* partition(ListNode* head) {
ListNode* odd = head;
ListNode* evenHead = head->next;
ListNode* even = evenHead;
while (even != nullptr && even->next != nullptr) {
odd->next = even->next;
odd = odd->next;
even->next = odd->next;
even = even->next;
}
odd->next = nullptr;
return evenHead;
}
//leetcode206反转链表
ListNode* reverseList(ListNode* head) {
ListNode* prev = nullptr;
ListNode* cur = head;
while (cur != nullptr) {
ListNode* tmp = cur->next;
cur->next = prev;
prev = cur;
cur = tmp;
}
return prev;
}
//leetcode21合并两个有序链表
ListNode* sortList(ListNode* l1, ListNode* l2) {
if (l1 == nullptr) {
return l2;
} else if (l2 == nullptr) {
return l1;
} else if (l1->val <= l2->val) {
l1->next = sortList(l1->next, l2);
return l1;
} else {
l2->next = sortList(l1, l2->next);
return l2;
}
}
ListNode* sortLinkedList(ListNode* head) {
if (head == nullptr || head->next == nullptr) {
return head;
}
ListNode* evenHead = partition(head);
evenHead = reverseList(evenHead);
return sortList(head, evenHead);
}
};