题解 | #把数字翻译成字符串#
数组中出现次数超过一半的数字
http://www.nowcoder.com/practice/e8a1b01a2df14cb2b228b30ee6a92163
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# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param numbers int整型一维数组
# @return int整型
#
class Solution:
def MoreThanHalfNum_Solution(self , numbers: List[int]) -> int:
# write code here
mid=len(numbers)/2
list1=[]
count=[]
if len(numbers)==1:
return numbers[0]
for i in range(len(numbers)):
if numbers[i] not in list1:
list1.append(numbers[i])
count.append(1)
else:
index_number=list1.index(numbers[i])
count[index_number]+=1
if count[index_number]>mid:
sol=numbers[i]
return sol
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param numbers int整型一维数组
# @return int整型
#
class Solution:
def MoreThanHalfNum_Solution(self , numbers: List[int]) -> int:
# write code here
mid=len(numbers)/2
list1=[]
count=[]
if len(numbers)==1:
return numbers[0]
for i in range(len(numbers)):
if numbers[i] not in list1:
list1.append(numbers[i])
count.append(1)
else:
index_number=list1.index(numbers[i])
count[index_number]+=1
if count[index_number]>mid:
sol=numbers[i]
return sol