题解 | #输出单向链表中倒数第k个结点#

while True:
    try:
        n = int(input().strip())
        in_lb = input().strip().split()
        out_n = int(input().strip())

        if out_n == 0:
            print(0)
        elif len(in_lb) > 1:
            print(in_lb[-out_n])
        else:
            print(0)
    except EOFError:
        break