题解 | #求解立方根#
求解立方根
http://www.nowcoder.com/practice/caf35ae421194a1090c22fe223357dca
f(x)=x^3-n
f'(x)=3x^2
所以有xn+1=xn-(xn^3-n)/(3xn^2)
cin>>x;
int b=1.0,a=0.0;
while(abs(b-a)>0.001){
a=b;
b=a-(a*a*a-x)/(3*a*a);
}
printf("%.1f",b);
求解立方根
http://www.nowcoder.com/practice/caf35ae421194a1090c22fe223357dca
f(x)=x^3-n
f'(x)=3x^2
所以有xn+1=xn-(xn^3-n)/(3xn^2)
cin>>x;
int b=1.0,a=0.0;
while(abs(b-a)>0.001){
a=b;
b=a-(a*a*a-x)/(3*a*a);
}
printf("%.1f",b);
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