题解 | #句子逆序#

C语言，根据题意无脑模拟

#include <stdio.h>

int main() {
    char ch[1005]; //输入
    gets(ch);
    char ans[1005][1005]; //输出
    int hang = 0, lie = 0;
    for (int i = 0; i < strlen(ch); i++) {
        if (ch[i] == ' ') { //每次遇到空格，就是字符串加一
            hang++;
            lie = 0;
        } else 
            ans[hang][lie++] = ch[i];
    }
    for (int i = hang; i >= 0; i--) { //倒着输出结果字符数组
        printf("%s", ans[i]);
        i & printf(" ");
    }
    printf("\n");
    return 0;
}