题解 | #简单密码#

#include <stdio.h>
#include <string.h>

int main(void)
{
    char input[1000];
    char output[1000] = "\0";
    int Nnum = 0,Enum = 0,Knum = 0,Onum = 0;
    gets(input);
    {
        for(int i=0;i<strlen(input);i++)
        {
            if(input[i] >= 'A' && input[i] <= 'Z')//大写
            {
                if(input[i] == 'Z')
                    output[i] = 'a';
                else
                    output[i] = input[i] + 32 + 1;//转换为小写
            }
            else if(input[i] >= 'a' && input[i] <= 'z')//小写
            {
                if(input[i]>='a' && input[i]<='c')
                    output[i]='2';
                else if(input[i]>='d' && input[i]<='f')
                    output[i]='3';
                else if(input[i]>='g' && input[i]<='i')
                    output[i]='4';
                else if(input[i]>='j' && input[i]<='l')
                    output[i]='5';
                else if(input[i]>='m' && input[i]<='o')
                    output[i]='6';
                else if(input[i]>='p' && input[i]<='s')
                    output[i]='7';
                else if(input[i]>='t' && input[i]<='v')
                    output[i]='8';
                else if(input[i]>='w' && input[i]<='z')
                    output[i]='9';
            }
            else//数字
                output[i] = input[i];
        }
        printf("%s\n",output);
        return 0;
    }
}