题解 | 妙策
在二叉树中找到两个节点的最近公共祖先
http://www.nowcoder.com/practice/e0cc33a83afe4530bcec46eba3325116
public class Solution {
public int lowestCommonAncestor (TreeNode root, int o1, int o2) {
return (LCA(root, o1, o2)).val;
}
public static TreeNode LCA(TreeNode root, int o1, int o2){
if(root == null || root.val == o1 || root.val==o2){
return root;
}
TreeNode left = LCA(root.left, o1, o2);
TreeNode right = LCA(root.right, o1, o2);
//如果左树和右树都不为空,则返回头部
if(left != null && right != null){
return root;
}
return left != null ? left : right;
}
}
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