题解 | #删除字符串中出现次数最少的字符#

using namespace std;

int main(){
    string s;
    while(cin >>s){
        map<char, int> map;
    for(int i = 0; i < s.size(); i++){
        if(map.find(s[i]) != map.end()){
            map[s[i]] += 1;
        }else{
            map[s[i]] = 1;
        }
    }
    int min = 20;
    for(auto it : map){
        min = min > it.second?it.second:min;
    }
    for(int i = 0; i < s.size(); i++){
        if(map[s[i]] == min){
            continue;
        }
        cout << s[i];
    }
    cout << endl;
    }
    
    return 0;
}