题解 | #【模板】完全背包#
【模板】完全背包
http://www.nowcoder.com/practice/237ae40ea1e84d8980c1d5666d1c53bc
和01背包的区别就是可以无限取一个物品,这样就要求外循环是容量,内循环是物品的种类
利用二维循环也是比较好理解
for (int i = 1; i <= n; i++) {
for (int j = v[i]; j <= V; j++) {
int num = j / v[i];
for (int k = 1; k <= num; k++) {
dp[i][j] = Math.max(dp[i - 1][j], dp[i - 1][j - k * v[i]] + k * w[i]);
}
}
}
import java.util.Arrays;
import java.util.Scanner;
/**
* @program: springDemo
* @author: JiaLe Hu
* @create: 2022-03-18 16:02
**/
public class Main {
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
int n = reader.nextInt();
int V = reader.nextInt();
int[] v = new int[n + 1];
int[] w = new int[n + 1];
for (int i = 1; i <= n; i++) {
v[i] = reader.nextInt();
w[i] = reader.nextInt();
}
// init
int[] dp = new int[V + 1];
Arrays.fill(dp, Integer.MIN_VALUE);
dp[0] = 0;
// dp[i][j] = dp[i - 1][j], dp[i - 1][j - nums * v[i]] + num * w[i];
for (int i = 0; i <= V; i++) {
for (int j = 1; j <= n; j++) {
if (i >= v[j]) {
dp[i] = Math.max(dp[i], dp[i - v[j]] + w[j]);
}
}
}
int res = 0;
for (int i = 1; i <= V; i++) {
res = Math.max(res, dp[i]);
}
System.out.println(res);
System.out.println(Math.max(dp[V], 0));
}
}