题解 | #斐波那契数列#
斐波那契数列
http://www.nowcoder.com/practice/c6c7742f5ba7442aada113136ddea0c3
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# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
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# @param n int整型
# @return int整型
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class Solution:
def Fibonacci(self , n: int) -> int:
# write code here
m=1
sum=1
if n<=2:
return 1
else:
for i in range(2,n):
m,sum=sum,sum+m
return sum