题解 | #KY196 复数集合#
复数集合
http://www.nowcoder.com/practice/abdd24fa839c414a9b83aa9c4ecd05cc
解法一
#include <iostream>
#include <vector>
#include <queue>
#include <string>
#include <math.h>
using namespace std;
struct cmp {
pair<double, int> stringToValue(string s) {
int pos1 = s.find("+i");
string s1 = s.substr(0, pos1);
string s2 = s.substr(pos1+2);
int a = stoi(s1);
int b = stoi(s2);
double v = sqrt(a*a + b*b);
return {v, b};
}
bool operator() (string s1, string s2) {
pair<double, int> v1 = stringToValue(s1);
pair<double, int> v2 = stringToValue(s2);
if (v1.first == v2.first) return v1.second > v2.second;
else return v1.first < v2.first;
}
};
priority_queue<string, vector<string>, cmp> pq;
int main()
{
int n;
while (cin >> n) {
while (n--) {
string s;
cin >> s;
if (s == "Pop") {
if (pq.size() == 0) {
cout << "empty" << endl;
}
else {
string tmp = pq.top();
cout << tmp << endl;
pq.pop();
int size = pq.size();
cout << "SIZE = " << size << endl;
}
}
if (s.find("Insert") != string::npos) {
string numStr;
cin >> numStr;
pq.push(numStr);
int size = pq.size();
cout << "SIZE = " << size << endl;
}
}
}
return 0;
}
解法二
#include <iostream>
#include <vector>
#include <queue>
#include <string>
#include <math.h>
using namespace std;
struct Complex {
int real;
int imag;
Complex(int a, int b) : real(a), imag(b) { }
friend bool operator < (const Complex& c1, const Complex& c2) {
return pow(c1.real,2) + pow(c1.imag,2) < pow(c2.real,2) + pow(c2.imag,2);
}
};
int main()
{
priority_queue<Complex> pq;
int n;
while (cin >> n) {
while (n--) {
string s;
cin >> s;
if (s == "Pop") {
if (pq.size() == 0) {
cout << "empty" << endl;
}
else {
Complex tmp = pq.top();
printf("%d+i%d\n", tmp.real, tmp.imag);
pq.pop();
int size = pq.size();
cout << "SIZE = " << size << endl;
}
}
if (s.find("Insert") != string::npos) {
int a, b;
scanf("%d+i%d", &a, &b);
pq.push(Complex(a,b));
int size = pq.size();
cout << "SIZE = " << size << endl;
}
}
}
return 0;
}