题解 | #出现三次以上相同积分的情况#
出现三次以上相同积分的情况
http://www.nowcoder.com/practice/c69ac94335744480aa50646864b7f24d
select t1.number
-- , count(t1.number) AS count_num
from grade t1
group by t1.number
-- having count_num > 2
having count(t1.number) > 2
-- having count(1) > 2
-- having count(*) > 2
-- , count(t1.number) AS count_num
from grade t1
group by t1.number
-- having count_num > 2
having count(t1.number) > 2
-- having count(1) > 2
-- having count(*) > 2
order by t1.number asc
group by 字段 和 having count(字段) 中 可以是同一个字段。
