题解 | #查找输入整数二进制中1的个数#

while True:
    try:
        num = int(input())
        a = bin(num) #十转二
        a = list(a)
        count = 0
        for i in a:
            if(i == '1'): #找1的个数
                count += 1
        print(count)
    except:
        break