题解 | #字符统计#
字符统计
http://www.nowcoder.com/practice/c1f9561de1e240099bdb904765da9ad0
while True:
try:
words = input()
s = sorted(set(words))// 用 set 去掉多余的数字，进行第一步按ACSII码来排序
ss = sorted(s, key = lambda x:words.count(x),reverse=True)//通过key=lambda再按照次数进行排序
print("".join(ss))
except:
break
