题解 | #密码强度等级#

用函数判断密码长度、是否包含大小写字母、是否包含数字、是否包含符号并返回对应分值，再写一个评判函数。避免直接判断然乱思路。

def length(n):
    if len(n) <= 4:
        return 5
    elif 5 <= len(n) <=7:
        return 10
    elif 8 <= len(n):
        return 25

def alpha(n):
    alpha_list = []
    upper_list = []
    lower_list = []
    for i in n:
        if i.isalpha():
            alpha_list.append(i)
        if i.islower():
            lower_list.append(i)
        elif i.isupper():
            upper_list.append(i)
    if len(alpha_list) == 0:
        return 0
    if len(lower_list) != 0 and len(upper_list) == 0:
        return 10
    if len(lower_list) == 0 and len(upper_list) != 0:
        return 10
    if length(upper_list) != 0 and len(lower_list) != 0:
        return 20

def number(n):
    num_list = []
    for i in n:
        if i.isdigit():
            num_list.append(i)
    if len(num_list) == 0:
        return 0
    if len(num_list) == 1:
        return 10
    if len(num_list) > 1:
        return 20

def symbol(n):
    symbol_list = []
    st = '!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~'
    for i in n:
        if i in st:
            symbol_list.append(i)
    if len(symbol_list) == 0:
        return 0
    if len(symbol_list) == 1:
        return 10
    if length(symbol_list) > 1:
        return 25

def reward(n):
    if alpha(n) != 0 and number(n) != 0 and symbol(n) == 0:
        return 2 
    if alpha(n) == 10 and number(n) != 0 and symbol(n) != 0:
        return 3
    if alpha(n) >= 20 and number(n) > 0 and symbol(n) > 0:
        return 5
    else:
        return 0

def score(n):
    total = length(n) + alpha(n) + number(n) + symbol(n) + reward(n)
    if total >= 90:
        print('VERY_SECURE')
    elif 80 <= total < 90:
        print('SECURE')
    elif 70 <= total < 80:
        print('VERY_STRONG')
    elif 60 <= total < 70:
        print('STRONG')
    elif 50 <= total < 60:
        print('AVERAGE')
    elif 25 <= total < 50:
        print('WEAK')
    else:
        print('VERY_WEAK')

while 1:
    try:
        key = input()
        score(key)
    except:
        break