题解- 数组 | #矩阵乘法#

while True:
    try:
        x = int(input())
        y = int(input())
        z = int(input())
        x_y = [[0 for i in range(y)] for j in range(x)]
        y_z = [[0 for i in range(z)] for j in range(y)]
        result = [[0 for i in range(z)] for j in range(x)]
        for i in range(x):
            set_y = list(map(int,input().split()))
            for j in range(y):
                x_y[i][j]=set_y[j]
        for i in range(y):
            set_z = list(map(int, input().split()))
            for j in range(z):
                y_z[i][j]=set_z[j]
                
        for i in range(x):
            for j in range(z):
                sum = 0
                for k in range(y):
                    sum+=x_y[i][k]*y_z[k][j]
                result[i][j]=sum
            print(" ".join(list(map(str,result[i]))))
    except:
        break

好像无法插入numpy数据库，只能用循环一点点算了。一些常见的操作可以背下来，写代码会更快点：

1. 将一次性输入的数据转化为数组：

set_x = list(map(int, input().split()))

2. 将数组打印出来

print(" ".join(list(map(str,set_x))))

3. 在python中用列表生成式来表示矩阵

[[0 for i in range(n)] for j in range(m)]

生成一个m*n 的矩阵