题解 | #简单计算器#
简单计算器
http://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239
需要注意一点就是 需要double类型,最后一个测试题才能精度准确
#include<stdio.h>
int main()
{
double a,b;
char c;
scanf("%lf%c%lf",&a,&c,&b);
if(c!='+'&&c!='-'&&c!='*'&&c!='/') printf("Invalid operation!\n");
else if(c=='+') printf("%.4lf+%.4lf=%.4lf",a,b,a+b);
else if(c=='-') printf("%.4lf-%.4lf=%.4lf",a,b,a-b);
else if(c=='*') printf("%.4lf*%.4lf=%.4lf",a,b,a*b);
else if(c=='/')
{
if(b==0.0) printf("Wrong!Division by zero!\n");
else printf("%.4lf/%.4lf=%.4lf",a,b,a/b);
}
return 0;
}
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