题解 | #反转链表#
反转链表
http://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
/* struct ListNode { int val; struct ListNode next; ListNode(int x) : val(x), next(NULL) { } };/ class Solution { public: ListNode* ReverseList(ListNode* pHead) {
ListNode* pNew = NULL;
while(pHead != NULL){
ListNode* temp = pHead->next;
pHead->next = pNew;
pNew = pHead;
pHead = temp;
}
return pNew;
}
};