题解 | #整数中1出现的次数（从1到n整数中1出现的次数）#

public:
    int NumberOf1Between1AndN_Solution(int n) {
        int i;
        int sum=0;
        for(i=1;i<=n;i+=1){
            sum+=judge(i);
        }
        return sum;
    }
    
    int judge(int n){
        int result;
        int count=0;
        while(n!=0){
            result=n%10;
            if(result==1){
                count+=1;
            }
            n/=10;
        }
        
        return count;
    }
};