题解 | #字符串最后一个单词的长度#

#include<iostream>
#include<string>
using namespace std;

class solution {
public:
    solution(string p):s(p)
    { }

     void lastworld_len() {
        int i = s.length() - 1;
        if (s[i] > 90 && s[i] < 97 || s[i]>122 || s[i] < 65) {//这里要考虑字符串s是否包含换行、空格等非字母的字符
            while (s[i] > 90 && s[i] < 97 || s[i]>122 || s[i] < 65) {
                --i;
            }
        }
        int j = i;
        while (s[i] >= 65 && s[i] <= 90 || s[i] >= 97 && s[i] <= 122) {
            --i;
        }
        cout << j - i << endl;
    }
private:
    string s;
};

int main(){
    string s ;
    getline(cin, s);
    solution so(s);
    so.lastworld_len();
    return 0;
}