题解 | #二进制中1的个数#
二进制中1的个数
http://www.nowcoder.com/practice/8ee967e43c2c4ec193b040ea7fbb10b8
int NumberOf1(int n )
{
int count = 0;
while(n)
{
n = n&(n-1);
count++;
}
return count;
}
二进制中1的个数
http://www.nowcoder.com/practice/8ee967e43c2c4ec193b040ea7fbb10b8
int NumberOf1(int n )
{
int count = 0;
while(n)
{
n = n&(n-1);
count++;
}
return count;
}
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